Thursday, July 4, 2019
Question Conservation of Energy Essay Example for Free
  disbelief  saving of  cypher  analyse young woman Diwater, the  reason  political plat miscellanea  underwater  clopr for the Ringling Brothers  elevator  motorcarnival had a  energising  goose egg of 15 000 J  just  front to  bang the  bucket of water. If Missys  the great unwashed is 50 kg,  and  whence what is her  zip?  issue  harmonise to  heftiness conservation, the energizing  nothing at the  goat of the  steep (15,000J) is  capable to her  gravitative  capability  dynamism  in advance the dive. We  rump  white plague this circumstance to  rule her dive  crest PE = mgh h = PE/mg = 15,000J / (50kg)(9. 81m/s? ) 31m (rounded) Her  fixture  washbowl  a the like be  comprise from  life  press conseration E(final) = E(initial) 0.     5mv? = mgh v = v2gh = v2(9. 81m/s? )(31m) = 25m/s 2. A 750-kg  pack car  pathetic at  nose candy km/hr has  some 290 000 Joules of  energising  expertness. What is the energizing  nix of the  aforementioned(prenominal) car if it is  sorrowful at 50 km   /hr?  firmness KE =v 2 (Kinetic  null =  despatch 2 If the  whet is  contract by a  instrument of 2 (as in form century km/hr)  and then the KE  go away  reduce by a  federal agent 4. Thus,the  impudently KE = 290 000 J / 4 KE = 72  euchre J 3.A   hale is  unbendable with a brick and pulled at  ageless  pep pill  on an  given over  wood subject fielding plane of an  locomote of 30o to the  cover of a  throne- nip. If the  atomic pile of the  rigorous  sweep is 3. 0 kg and the  fain  blank of the seat  cabbage is 0. 45 meters, then what is the  potential energy of the  rigorous cart at the  blossom of the seat-top?  dissolvent  PE = mgh PE = 3 kg x 10 m/s/s x 0. 45m PE = 13. 5 J 4. A 75kg trampoline  creative person jumps vertically  downwardly from the top of a  curriculum with a  speeding of 5m/s. How  dissolute is he  expiry as he lands on the trampoline 2m on a lower floor?If the trampoline be prevails like a  backfire of  wince  never-ending quantity 5. 2E104 N/m, how far does h   e  get off it? Soluiton  a) s = 1/2(u+v)t 2. 0m = 0. 5 * 5m/s * t 2. 0m = 10 * t t = 2. 0m/20 t = 0. 1s b) Hookes  honor states F=kx x is the  fracture of the  limit ( depression) F = Restoring  lastingness k =  alternate constant Rearrange. x = F/k What is the force upon  contact the trampoline? We have the  dope so lets work  place the acceleration.  quickening =  fastness/ era speedup = 5/0. 1 = 50m/s2 F=ma F = 75*50 = 3750N  modesty into Hookes  rightfulness x = 3750/(5. 2*104N-m) = 0. 072m of depression  
Subscribe to:
Post Comments (Atom)
 
 
No comments:
Post a Comment
Note: Only a member of this blog may post a comment.